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Integrating Factors for Differential Equations: Example 6
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Solve the differential equation,
, by testing whether an integrating factor can be found. If it can be found, complete the solution.
What is the general form of this differential equation?.
What is a condition for determining an integrating factor?
One condition is
Find
.
Find
Determine the above condition.
Is this a function of only
x
?
Yes,
What is our conclusion?
That there is an integrating factor.
How do we find it?
The integrating factor is
Lets focus on the integral
. Set it up.
We get
Use this result to set up the integrating factor.
We get
for the
integrating factor
.
What do we do with this integrating factor?
We multiply the original differential equation by it.
Do that.
Our
modified differential equation
becomes
Is this now an exact differential equation?
Yes.
How do we proceed?
We partially integrate one of the terms.
The
dy
term is simpler here.
Set up that integral to get the solution
U(x,y)
.
Do the integral.
Why do we get the
g(x)
term?
Because we did a partial integration with respect to
y
.
How do we determine
g(x)
?
We can determine
from this result and compare it with the coefficient of the
dx
term of the modified differential equation. The two must be equal.
Take the partial derivative.
We get
Compare this with the modified differential equation.
They are the same except for the
term.
What can we conclude about
?
We see that it must be zero.
How can we use this result?
We can do a partial integration with respect to
x
.
Do it.
Combine these results to obtain the general solution.
is the solution of our modified differential equation.
Check this result by calculating
in agreement with the
dx
term in the modified differential equation.
Check by calculating
in agreement with the
dy
term in the modified differential equation.
The end.
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General Contents
Detailed Contents
Index