After checking for factoring we see that this can be written as

Hence, except at x = 2, where the cancelation can not be done because the denominator is 0, the problem becomes

, as indicated in the graph.

Here we use the rules for the limits of power, constant multiple, and sums to get

From the Theorem on Limits we see that the function need not be defined at x = 2 for the limit to exist.