Continuity: 1 removable, 1 not removable: linear over quadratic: ![]()
Determine whether this function is continuous. If it is discontinuous, is the discontinuity removable?
We can factor the denominator and then use the Definition of Continuity:
. We see that except at x = 3,
. For a solution at points other than x = 3, see the related problem.
When x = 3, we cannot cancel and we must work with the original function.
Is the function defined at x = 3? No, it is not defined where the denominator becomes zero, or x = 3.
Does the function have a limit at the same point? Since the one-sided limits do not involve the point, we can still cancel: we need
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Since these limits are equal, the limit exists at x = 3.
Can the discontinuity be removed? Yes, the function can be separately defined to equal its limit, making the discontinuity removable.