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Integral of the quotient of sums of exponentials:

We need to try a substitution. Our strategy is to substitute u for the denominator in the hopes that the remainder of the integrand will provide du, except for a constant.

Let . Then .

Upon substitution of these results, we get

Hence, we can use the integral resulting in ln:

.

Finally, we substitute for u to get the result in terms of x:

General Contents

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