Integral of the exponential of a linear factor:

If the correct factors are present, this can be handled by the integral of the exponential function:

, where ; .

With this substitution, we get

Finally, we substitute for u to get the result in terms of x:

Notice that the exponent of the resulting function is the same as that in the original problem.

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This video is brought to you by Brightstorm, where you can see over 2,000 free math videos. See more Substitutions Involving e^x or ln(x) videos at Brightstorm.