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Minimize the distance from a curve:

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Find the coordinates of a point on the curve equation of thee parabolawhich is closest to the point (5,0).

graph of the parabola and a general point 

We can minimize the square of the distance, just as well as the distance itself. We will have an easier equation to work with as a result:

equation of the square of the distance

Since the point must be on the given curve, the y coordinate can be replaced by its equivalent in terms of x. Hence we can express the square of the distance entirely in terms of x:

the square of the distance

In order to minimize this, we differentiate and set the result to 0. First, the derivative is

derivative of the square of the distance

If we set this to 0 to find the coordinates of the closest point , we get

, or x-coordinate of the closest point on the parabola

We can find the corresponding y coordinate from the equation of the curve:

y-coordinate of the closest point on the parabola

Hence (4.5, 2.12) are the coordinates of the desired closest point on the original curve to the point (5,0). We can find the actual distance by substituting in the equation for the square of the distance and taking the square root:

, or the distance to the closest point

Test Problem: Find the coordinates of the point on equation of the parabolaclosest to (6, 0).


the coordinates of the closest point to the parabola in the test problem


General Contents

Detailed Contents

Index