General Contents

More Velocity, Acceleration Problems

Index

Maximum height of a ball


If you find this page helpful and would recommend that I create more pages like this one, please let me know: Email to John Taylor

The position of a ball thrown from a cliff is given by

equation of motion under gravity

We can determine the maximum height of the ball by differentiating, setting the derivative to 0, and solving for the time, tmax. Then the maximum height is found by using tmax in y(t):
.
First find tmax:

equation for velocity of thrown ball

Setting this to 0, we get 0 = 64 – 32 tmax, or tmax = 2.

Now, we can find the maximum height:

determination of the maximum heightft

Note the physical meaning of . It means that the velocity is momentarily 0 at the highest point on the path.
Note also that

second (2nd) derivative ft/sec/sec.
This negative value of the second derivative is consistent with the occurrence of a maximum.

If you find this page helpful and would recommend that I create more pages like this one, please let me know: Email to John Taylor

Test Problem: Solve the same problem with

equation of motion of another thrown ball

tmax ymax
0.5 96.25
4.0 60
1.94 15.2
2.0 130

General Contents

More Velocity, Acceleration Problems

Index