grams/sec,
where R is the rate of the reaction and T is in degrees Celsius.
We can find Tmax, the temperature at which the rate is a maximum, by differentiating and setting the derivative to 0.
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At Tmax, this expression equals 0:

From this, we get
, or
deg C.
This is the temperature at which the maximum rate occurs. To get the maximum rate, Rmax, itself, we can substitute into the equation for the rate:
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Test Problem: Find the values of Tmax and Rmax for
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| Tmax | Rmax | |
| 15.8 | 56000 | |
| 6.30 | 5694 | |
| 3.98 | 6872 |