Find the critical values of a cubic:
![]()
The extrema or critical values are located where the derivative of f(x) is zero. We can use the Power, Scalar Multiple, and Sum Rules to get
![]()
Setting this to 0 and factoring, we get
![]()
Since f ' is defined for all values of x, the critical numbers are -3 and +2.
Next we wish to use the First Derivative Test to determine the slope of the graph of f(x) in the 3 intervals defined by these two values as shown in the following table:
|
Interval |
To left of -3 |
Between -3 and 2 |
To the right of 2 |
|
Point in interval |
-4 |
1 |
3 |
|
Sign of f '(x) at point |
+ |
- |
+ |
|
Character of graph of f(x) at point |
rising |
falling |
rising |
|
Sketch
|
|
|
|
From the table we conclude that the function f(x) must have a maximum at x = -3 and a minimum at x = +2.
Test Problem: Determine the location and nature of the critical points for
![]()
Which of the following are the x-coordinates of the critical points?
a) 1 and -4
b) -1 and 4
c) -1 and -4
d) 1 and 4
Or you can return to the beginning of sample problem.