Differentials: Estimate a root: ![]()
We can handle this with the function
. Since this can be evaluated exactly at x = 32
, we can use differentials to determine the change in the root when the value of x changes by 0.5:
![]()
Evaluating this at x = 32, we have
![]()
Hence the fifth root of 32.5 can be found using this change in the root: ![]()
For comparison, taking the root directly on a calculator, we get 2.00621.