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Derivative of the tangent of a fractional power:

Via the Scalar Multiple rule, we can treat this as.

We can go a step further and consider it as involving a quantity u:

, where .

When we eventually apply the Chain Rule, we'll need

.

Combining these partial results and using the derivative of the tangent, we get

Finally, we substitute for u:

Note that the argument of the secant in the result is the same as the argument of the tangent in the original problem.

General Contents

Detailed Contents

Index